Let’s do a real example problem of how you’d do a calculation for figuring out how much oxygen you would need for the complete combustion of 454 grams of propane.
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Comments

3 Responses to “Chemical Analysis on Weight”

  1. The error Andrea mentioned is when you are calculating the number of moles of H2O (time stamp 7:48) 10.3 mol C3H8 x (4mol H2O/ 1 mol C3H8) = 41.2 mol H2O, not the 4.12 mol that is written. However your final calculation is still correct because you do not use this conversion to solve for your final answer.

  2. I am not seeing this error in the video… can you be more specific (provide a time index?) I don’t see this error in the calculations after watching the video, but I might have totally missed it. I have for a final answer for the mass of H20 = 740 g.

  3. andrea alfred says:

    We thought you might want to correct your mistake with your math (the decimal was wrong, it should be 41.2mol H2O, not 4.12mol H2O).